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98x^2+196x-4704=0
a = 98; b = 196; c = -4704;
Δ = b2-4ac
Δ = 1962-4·98·(-4704)
Δ = 1882384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1882384}=1372$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(196)-1372}{2*98}=\frac{-1568}{196} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(196)+1372}{2*98}=\frac{1176}{196} =6 $
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